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Tutorial Math 204
Tutorial 1
System of linear equations
Gauss / Gauss - Jordan reduction
by Rogelio Yoyontzin
# Tutorial Math 204
Tutorial 1
System of linear equations
Gauss / Gauss - Jordan reduction

## Problem 1

### Find the augmented matrix of the system

### Gauss/Gauss Jordan Reduction

### The system with zeros

### Reduce echalon form

### Is this the best way to solve it?

## Probelm 2 to be solved in the blackboard

## Problem 3 to be solved in the
Blackboard by students

## Problem 4

## Important Points To Remark

### How to write the steps in the Aug.Coeff.Matrix(ACM). Write
the ACM and beside it state the Elementary Row
Operation(ERO) to be executed.

### What happens when a 1 cannot be determined on a row?

### Start at the bottom of the final ACM when interpreting the
final solution.

### How the General solution is to be written with parameters
and also a couple of particular solutions

### how to avoid fractions until the last ERO is to be done. You
do not have to get the ones first. Get the zeros first if it helps
to avoid fractions (see 5c in notes)

## First Find The Augmented Matrix
of the following examples:

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Ph. D Candiate: Jesús Rogelio Pérez Buendía. If you want to send me an email please use Moodle email service. You can Find me on The Math Help Centre LB 912. You will hae acces to this matherial on Moodle Meta Site. You will have a 15 min Quiz based on one (similar) exercise on this asignment and/or Tutorial problems for next week.

There are three types of elementary row operations which may be performed on the rows of a matrix: Type 1: Swap the positions of two rows. Type 2: Multiply a row by a nonzero scalar. Type 3: Add to one row a scalar multiple of another.

The Augmented Matrix is:, Now we use the algorithm, Second operation, 3rd operation, 4th operation, 5th operation, 6th operation, 7th operation, 8th operation, 9th operation, 10th operation

Specifically, a matrix is in row echelon form if All nonzero rows (rows with at least one nonzero element) are above any rows of all zeroes (all zero rows, if any, belong at the bottom of the matrix). The leading coefficient (the first nonzero number from the left, also called the pivot) of a nonzero row is always strictly to the right of the leading coefficient of the row above it. All entries in a column below a leading entry are zeroes (implied by the first two criteria).[1] Some texts add the condition that the leading coefficient of any nonzero row must be 1.[2]

What is it?

So…? No equation of this system has a form zero = nonzero; Therefore, the system is consistent. The leading entries in the matrix have been highlighted in yellow. A leading entry on the (i,j) position indicates that the j-th unknown will be determined using the i-th equation.

Then… Those columns in the coefficient part of the matrix that do not contain leading entries, correspond to unknowns that will be arbitrary. The system has infinitely many solutions:

For a computer YES (almost)

For Humans NO… Let's try to solve it easier., Go to this site: