Mole Concept and Stoichiometry

Mole concept and Stoichiometry quick revision guide.

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Mole Concept and Stoichiometry 저자: Mind Map: Mole Concept and Stoichiometry

1. MF = (EF)n

2. Empirical and molecular formula

2.1. Empirical formula - gives the simplest ratio of the atoms of elements in a compound.

2.2. Mol. formula - gives actual ratio of atoms of elements in a compound.

2.3. 1. Identify the elements

2.4. 2. note down % composition

2.5. 3. note down at. mass

2.6. 4. AR = %comp/at. mass

2.7. 5. SAR = AR/least AR

2.8. 6. Round off SAR to the closest whole no.

2.9. n = RMM/EFM

3. Percentage composition

3.1. Find RMM

3.2. Mass of element x 100 / RMM

4. Mass-mass and volume -volume relationship

4.1. Identify the compounds related

4.2. Find RMM of compounds if mass is given/ asked for

4.3. Remember to use stoichiometric coefficients from the balanced eqn.

4.4. If vol is given or asked, use molar volume, multiply with appropriate stoichiometric coefficient.

5. VD = RMM/2

6. Gay Lussac's law

6.1. Gases react in volumes bearing simple whole no. ratio to each other and gaseous products.

6.2. Numericals - identify vol. ratio and calculate for given volume

6.3. identify limiting reagent if any when volume of unused gas/ composition of resulting mixture is asked.

7. Avogadro's law

7.1. Equal volumes of all gases - same no. of molecules.

7.2. VD = mass of certain vol of gas/ mass of same vol of H2

8. Mole concept

8.1. RMM - No. of times one molecule is heavier than 1/12th the mass of C - 12.

8.2. one mole

8.2.1. 22.4 litres = 22400cm3

8.2.2. 6.023 x 10^23 particles

8.2.3. 1 RAM/ 1 RMM in grams

8.2.4. same no. of particles as atoms in 12g C- 12

8.3. Molar volume

8.3.1. 22.4 litres = 22400cm3

8.3.2. volume occupied by 1mole of gas at STP

8.4. moles = mass/ RMM